0,6=0,10+v^2/2.9,8

Solution for 0,6=0,10+v^2/2.9,8 equation:

0.6=0.10+v^2/2.9.8

We move all terms to the left:

0.6-(0.10+v^2/2.9.8)=0

We get rid of parentheses

-v^2/2.9.8-0.10+0.6=0

We multiply all the terms by the denominator


-v^2-(0.10)*2.9.8+(0.6)*2.9.8=0

We add all the numbers together, and all the variables

-v^2-(0.1)*2.9.8+(0.6)*2.9.8=0

We add all the numbers together, and all the variables

-1v^2+1.16=0

a = -1; b = 0; c = +1.16;
Δ = b2-4ac
Δ = 02-4·(-1)·1.16
Δ = 4.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{4.64}}{2*-1}=\frac{0-\sqrt{4.64}}{-2}
=-\frac{\sqrt{}}{-2}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{4.64}}{2*-1}=\frac{0+\sqrt{4.64}}{-2}
=\frac{\sqrt{}}{-2}
$